Simple Ajax Upload image using jQuery PHP

Today, We want to share with you Simple Ajax Upload image using jQuery PHP.In this post we will show you how to insert image in database using ajax in php, hear for ajax image upload without refreshing page using jquery we will give you demo and example for implement.In this post, we will learn about Upload Image Without Page Refresh Using Ajax,jQuery And PHP with an example.

Simple Ajax Upload image using jQuery PHP

There are the Following The simple About Simple Ajax Upload image using jQuery PHP Full Information With Example and source code.

As I will cover this Post with live Working example to develop jquery ajax image upload with preview, so the some upload image using ajax in php for this example is following below.

Also Read :  Ajax File Upload without refreshing using jQuery and PHP

Upload image using ajax jquery

index.html

<html>
<head>
<title>Upload Image Using Ajax Example - pakainfo.com</title>
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.3/jquery.min.js"></script>
</head>
<body>
<form method="post" action="upload.php" id="upload">
<input type="file" name="img" value="" id="img">
<input type="submit" name="btn" value="Submit" />
</form>
<div id="img_preview"></div>
<script type="text/javascript">
jQuery("#upload").submit(function(e){
	jQuery.ajax({
			url: "do_upload.php",
			dataType: "json",
			type: "POST",             
			data: new FormData(this), 
			contentType: false,       
			processData:false,        
			cache: false,
			success: function(response){
			console.log(response);
			if(response.is_status == "1"){
				jQuery("#img").val("");
				jQuery("#img_preview").html('<img src='+response.img+'>');
			}else if(response.is_status == "0"){
				alert(response.msg);
			}
		}
	}); 
	e.preventDefault();
});
</script>
</body>
</html>

do_upload.php

When simple YOur Live image is uploaded to server side in PHP format it return output in sample json format.

<?php
$name = $_FILES['img']['name'];
$tname = $_FILES['img']['tmp_name'];
if(copy($tname, $name)){
	$res = array("is_status" => 1, "img" => $name);
}else{
	$res = array("is_status" => 0, "msg" => "error");
}
header("content-type: application/json");
echo json_encode($res);
?>

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